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3 years ago

How many square feet of carpet will we need for this hole

Mathematics

2 answers:

Ymorist [56]3 years ago

4 0

We don't know the size of the hole.

But that's OK. Whatever size the hole is, we're going to put the carpet AROUND it. We won't need any carpet at all for the hole itself.

The answer is 'zero'.

Inessa05 [86]3 years ago

3 0

Answer:

FIND THE HOLE SIZE IN THIS CASE THERE IS NO SIZE SO ZERO IS THE AWNSER

pls can i have brainliest

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Solve for v: -10=-5/4v

vagabundo [1.1K]

Answer:

v = 8

Step-by-step explanation:

-10= -5/4v first multiply both sides of the equation by -4/5

-10(-4/5) = v this cancels out the right side.

multiply the left side.

so you are left with 40/5 = v

next, simplify you will get 8=v

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3 years ago

Read 2 more answers

19. Subtract: 5 - 3 1/3 A. 3 1/3 B. 2 1/3 C. 1 2/3 D. 2 2/3

earnstyle [38]

Answer:

C. 1 2/3

Step-by-step explanation:

5 - 3 1/3

We can also convert 5 into a fraction with the same denominator like this:

Since we’re trying to make 5 a fraction with a denominator of 3, leave 4 as the whole number and 3/3 as the fraction

4 3/3

4 3/3 = 5 because 3/3 = 1 and 4 + 1 = 5

Now we can subtract!

4 3/3 - 3 1/3 = 1 2/3

Step 1. Subtract the whole numbers

Step 2. Subtract the numerator

Step 3. Leave the answer with the same denominator

4 0

3 years ago

HELP ME PLEASE WILL GIVE BRAINLIEST JUST HURRY GOT UNTIL TMRW AND ITS LATE LOL

antiseptic1488 [7]

Sergio will buy first! He is earning more than Lia per week, and it would take him about 34 weeks and he’d haves little money left over by that time :)

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3 years ago

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In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

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3 years ago

Find the slope of this graph, thanks

Anarel [89]

Slope = (change in 'y') / (change in 'x')

If you find two points where the line goes through the corners of boxes,
then count up the 'y' boxes and the 'x' boxes between those two points,
you'll find that the line rises 3 y-boxes for each x-box.

The slope of the line is 3 .

7 0

3 years ago