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xenn [34]
3 years ago
11

Why lie about my free answers );

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0
I like your sketchers
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If the mean of the data set is 84 points, find Haruka's final exam score in chemistry,
Pepsi [2]

The answer is 45 because if you divide 84 and 2 you get 42 and then add 3

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3 years ago
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5x + 10 &gt; 35<br> How do you work this out?
Alexxx [7]

Answer:

x > 5

Step-by -step explanation:

Solving inequalities is similar to solving equations.

5x + 10 > 35

Subtract 10 from both sides.

5x > 25

Divide by 5 from both sides to isolate the x.

x > 5

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3 years ago
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a solid sphere is cut into 3 equal wedges. the volume of each wedge is V=4/9π^3. solve the formula for r
algol13

\\ \qquad\quad\sf{:}\dashrightarrow V=\dfrac{4}{9}πr^3

  • It is one third of the solid. sphere

\\ \qquad\quad\sf{:}\dashrightarrow V_{(Sphere)}

\\ \qquad\quad\sf{:}\dashrightarrow 3\left(\dfrac{4}{9}πr^3\right)

\\ \qquad\quad\sf{:}\dashrightarrow \dfrac{4}{3}\pi r^3

Now

\\ \qquad\quad\sf{:}\dashrightarrow \pi r^3=\dfrac{3V}{4}

\\ \qquad\quad\sf{:}\dashrightarrow r^3=\dfrac{3V}{4\pi}

\\ \qquad\quad\sf{:}\dashrightarrow r=\sqrt[3]{\dfrac{3V}{4\pi}}

4 0
3 years ago
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Jeff decided to purchase a house, his mortage is a 30-year loan at 4.1 % compounded monthly. The final purchase price was $150,0
vredina [299]

Answer:

  $711.23

Step-by-step explanation:

We assume the entire closing cost went to reducing the principal of the loan. Then the amount borrowed was $147,192.

<h3>Monthly payment</h3>

The amortization formula tells you the monthly payment.

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

P is the principal, r is the annual rate, and t is the number of years.

The monthly payment is ...

  A = $147,192(0.041/12)/(1 -(1 +0.041/12)^-360) ≈ $711.23

Jeff's monthly payment is $711.23.

5 0
2 years ago
A taxi service has two rates, as follows: Rate A charges a flat $2.50 for every mile; rate B charges $15 plus $1.50 per mile. At
Marina CMI [18]
One must travel 16 miles before rate B becomes the cheapest rate.
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3 years ago
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