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3 years ago

14

Evaluate using long division first to write f(x) as the sum of a polynomial and a proper rational function. (Use C for the const

ant of integration. Remember to use absolute values where appropriate.)

1 answer:

OLEGan [10]3 years ago

3 0

Answer:

Step-by-step explanation:

Please kindly check the attached

(p(x))/(q(x))=f(x)+(r(x))/(q(x))

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Why is circle 1 similar to circle 2?

Artemon [7]

Circle 2 is a dial at ion of circle 1

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2 years ago

the difference between 2 whole numbers is 66. the ratio of the 2 numbers is 2:5, what are the 2 numbers

shtirl [24]

Answer:

44 and 110

Step-by-step explanation:

The ratio of the 2 numbers = 2 : 5 = 2x : 5x ( x is a multiplier ) , thus

difference = 5x - 2x = 3x , then

3x = 66 ( divide both sides by 3 )

x = 22

Thus

2x = 2 × 22 = 44

5x = 5 × 22 = 110

The 2 numbers are 44 and 110

8 0

3 years ago

Directions:Use the product rule to simplify the following monomials.

abruzzese [7]

7) Answer = $-24x^8y^{11}$

$\left(8x^4y^2\right)\left(-3x^4y^9\right)$

$=-8x^4y^2\cdot \:3x^4y^9$

$=-24x^4y^2x^4y^9$

$=-24x^8y^2y^9$

$=-24x^8y^{11}$

8) Answer = $-30y^6$

$2y\left(-5\right)y^2\cdot \:3y^3$

$=-30yy^2y^3$

$=-30y^{1+2+3}$

$=-30y^6$

9) Answer = $-6x^4y^5$

$\left(-2xy\right)\left(xy\right)\left(3x^2y^3\right)$

$=-2xyxy\cdot \:3x^2y^3$

$=-6xyxyx^2y^3$

$=-6x^4yyy^3$

$=-6x^4y^5$

3 0

2 years ago

WhAt is the answer to -12 - 3=-51

svet-max [94.6K]

Greetings!

Simplify both sides of the equation.
$-12 - 3=-51$
$-15 \neq -51$

Both sides of the equation are not equal.

Hope this helps.
-Benjamin

7 0

3 years ago

Carolyn leaves at 2:15 and drives 40 miles per hour. Marcel leaves at 2:45 and drives at 65 miles per hour. If they are travelin

Diano4ka-milaya [45]

Marcel leaves 30 minutes after Carolyn, leaving between them a gap of 40mph*0.5h=20miles
To catch up with the 20miles, Marcel uses the extra (65-40=25)mph that he has.
Therefore 20m/25mph=0.8h=0.8*60min=48minutes after 2:45, which is at 3:33, Marcel catches up to Carolyn.

8 0

3 years ago