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3 years ago

Ummm can u plz tell me what u put in these boxes and um answer 4 pls

Mathematics

1 answer:

Lorico [155]3 years ago

7 0

Well your answer for problem 4 is 28. IM not sure what the boxes are for though...

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Algebra help needed

lesantik [10]

Answer:

The ball will reach the ground when h=0.

Set the equation equal to 0.

$0=-8(2 t-4)(t+1)$

$t=-1,2$

Step-by-step explanation:

The height of a golf ball after it has been hit from the top of a hill can be modeled by the equation

$h=-8(2 t-4)(t+1)$ ,

where h is the height in feet and t is time in seconds.

When ball will reach the ground the distance between ball and ground is 0. So, the ball will reach the ground when h=0.

To find the time it takes for the ball to reach the ground, set the equation equal to 0 and use the Zero Product Property to solve for $t$.

$h=-8(2 t-4)(t+1)$

$\Rightarrow 0=-8(2 t-4)(t+1)$

Solve the equation using the Zero Product Property.

$2t-4=0\Rightarrow t=\dfrac{4}{2}=2$

$t+1=0\Rightarrow t=-1$

So, $t=-1,2$

7 0

3 years ago

G(C)=c(4c+8)(c-1) which values are equal to 0?

VashaNatasha [74]

Answer:

am is well ha all ha FL ha FL of all of all to the ell week of

4 0

3 years ago

Select the symbol that represents the phrase "at most."

anastassius [24]

Your answer will be c

4 0

3 years ago

Ok so Ive been having trouble with Math can anyone help??

Illusion [34]

For the first bit, put $930 + 7.5x and the second part is 58,000, 930 x 7.5 x 8

6 0

3 years ago

janelle wishes to finance a car for $33,000. the bank's annual interest rate is 3.5%, and she can choose between durations of fi

Harman [31]

Answer:

For a duration of 5 years, Monthly Payment =$600.42

For a duration of 6 years, Monthly Payment =$508.83

Step-by-step explanation:

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\$

where a= Amount to Finance=$33,000

Annual interest rate = 3.5%=0.035

r=Monthly Interest Rate= 0.035 ÷ 12 = $\frac{7}{2400}$

n=number of months to pay

For a duration of 5 years

n=5X12=60 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{60}}{(1+\frac{7}{2400})^{60}-1} \\=\dfrac{96.25 (1.1909)}{1.1909-1}\\=\dfrac{96.25 (1.1909)}{0.1909}\\=\dfrac{114.62}{0.1909}=\$600.42$

For a duration of 6 years

n=6X12=72 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{72}}{(1+\frac{7}{2400})^{72}-1} \\=\dfrac{96.25 (1.2333)}{1.2333-1}\\=\dfrac{96.25 (1.2333)}{0.2333}\\=\dfrac{118.71}{0.2333}=\$508.83$

4 0

3 years ago

Ummm can u plz tell me what u put in these boxes and um answer 4 pls ​

Ummm can u plz tell me what u put in these boxes and um answer 4 pls