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3 years ago

Ummm can u plz tell me what u put in these boxes and um answer 4 pls

Mathematics

1 answer:

Lorico [155]3 years ago

7 0

Well your answer for problem 4 is 28. IM not sure what the boxes are for though...

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The regular price of a winter coat is $65.50. It is on sale for $52.40. what is the percent decrease of the winter coat

marishachu [46]

I believe the percent decrease is 20%
as when you multiply 65.5 by 20%
it gives you 13.1
when you minus 13.1 from 65.50
it gives you $52.4

6 0

3 years ago

The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadr

Lostsunrise [7]

Since x represents the length (in meters), the width, which is 7 meters greater, is x +7. The product of these dimensions is the area (in square meters):
x(x +7) = 170
In standard form, the quadratic is ...
x² +7x -170 = 0

4 0

3 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

3 years ago

The question is show a dilation of a rectangle with a dilation of 8/3

miv72 [106K]

It's always easier to understand a concept by looking at specific examples with pictures, so I suggest looking at the dilation examples below first...before you try to internalize the steps listed below and that explain the general formula for dilating a point with coordinates of (2,4) by a scale factor of 1212.

1) multiply both coordinates by scale factor(2⋅12,4⋅122⋅12,4⋅12)2)

2. Simplify(1,2)3)

3. Graph(if required)

5 0

3 years ago

(Question is in the image) please I really need help

weqwewe [10]

Answer:

Step-by-step explanation:

The period is 1 complete cycle of the wave, before repeating.

1 cycle is from - 6 to - 2 , then

period = 4 → c

7 0

3 years ago

Ummm can u plz tell me what u put in these boxes and um answer 4 pls ​

Ummm can u plz tell me what u put in these boxes and um answer 4 pls