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morpeh [17]
3 years ago
7

Assume that Emily (who has CF, a recessive disease (aa)) decides to have children with a man who does not have CF and who has no

family history of CF. What combination of gametes can each of them produce, and what is the probability that they will have a child who is a carrier for CF?
Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:100%. Probability

Step-by-step explanation:

Emily = aa

Man = AA

After crossing the two, the result wI'll be Aa, Aa, Aa, Aa

Since every result has a carrier(a) in it, makes it 100% probability.

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Solve -4(3x-7) =40 for x
PIT_PIT [208]

Answer:

x = -1

Step-by-step explanation:

-4(3x-7) =40

Divide each side by -4

-4(3x-7)/-4 =40/-4

3x-7 = -10

Add 7 to each side

3x-7+7 = -10+7

3x = -3

Divide each side by 3

3x/3 = -3/3

x = -1

4 0
3 years ago
13 more than a number​
liberstina [14]

Answer:

x+13

Step-by-step explanation:

x +13

x: the number

7 0
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6 0
3 years ago
Military radar and missile detection systems are designed to warn a coutry of an enemy attack. Assume that a particular detectio
Tom [10]

Answer:

0.96 = 96% probability that at least one of them detect an enemy attack.

Step-by-step explanation:

For each radar, there are only two possible outcomes. Either it detects the attack, or it does not. The missiles are operated independently, which means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a particular detection system has a 0.80 probability of detecting a missile attack.

This means that p = 0.8

If two military radars are installed in two different areas and they operate independently, the probability that at least one of them detect an enemy attack is

This is P(X \geq 1) when n = 2. So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.8)^{0}.(0.2)^{2} = 0.04

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.04 = 0.96

0.96 = 96% probability that at least one of them detect an enemy attack.

6 0
3 years ago
Drag each expression to show whether it is equivalent to 6(4x−1), 24x+6, or (4⋅6x)+(4⋅2) somebody please help me i need to get t
faltersainse [42]

Answer:

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

Step-by-step explanation:

An equivalent expression is an expression which either simplified or factored is equal to it.

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

5 0
3 years ago
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