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Alenkinab [10]
3 years ago
12

Solve -4(3x-7) =40 for x

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

x = -1

Step-by-step explanation:

-4(3x-7) =40

Divide each side by -4

-4(3x-7)/-4 =40/-4

3x-7 = -10

Add 7 to each side

3x-7+7 = -10+7

3x = -3

Divide each side by 3

3x/3 = -3/3

x = -1

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What is the answer of 81g^2 - 36f^2 ?????
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Step-by-step explanation:

81g^2 - 36f^2 =

(9g)² - (6f)² =

(9g - 6f)(9g + 6f)

3 0
2 years ago
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allochka39001 [22]
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If the area of square is 2401 sqaure metre,find the perimeter of the sqaure​
Tcecarenko [31]

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6 0
3 years ago
Read 2 more answers
Pre-calc questions (trignometry)
miv72 [106K]

Answer:  (1a) 250°  (1b) 70°    (2) see below

<u>Step-by-step explanation:</u>

1a) -110 + 360 (one rotation clockwise) = 250°

1b) 430 - 360 (one rotation counterclockwise) = 70°

2) sec Ф = -8/5    in Quadrant III

Quadrant III identifies that both sin (y) and cos (x) are negative.

sec = r/x --> r = 8, x = -5, and y = -√39

(Use Pythagorean Theorem x² + y² = r² to solve for y)

\sin\theta=\dfrac{y}{r}=\dfrac{-\sqrt{39}}{8}              \csc\theta=\dfrac{r}{y}=\dfrac{-8}{\sqrt{39}}  rationalized = \dfrac{-8\sqrt{39}}{39}

\cos\theta=\dfrac{x}{r}=\dfrac{-5}{8}                  \sec\theta=\dfrac{r}{x}=\dfrac{-8}{5}  (GIVEN)

\tan\theta=\dfrac{y}{x}=\dfrac{\sqrt{39}}{5}              \cot\theta=\dfrac{x}{y}=\dfrac{-5}{-\sqrt{39}}  rationalized = =\dfrac{5\sqrt{39}}{39}

NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST.  Please repost #3 and #4 as a different question and I will answer them.

8 0
2 years ago
HELP PLEASE!! THIS IS DUE IN AN HOUR!!
Neko [114]

Answer:

Your answer is 30.

Step-by-step explanation:

You plug in b=12, and 5=h

12*5/2

60/2

--->30<---

7 0
3 years ago
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