Find the surface area of a basketball with a diameter of 10 in.
1 answer:
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Answer:
THE VALUE OF X = 3 .
Step-by-step explanation:
From the Δ RQP and Δ TSP ;
⇒ ∠ TPS = ∠ RPQ ( since both are common angle )
⇒ RQ ≈ TS ( parallel lines )
⇒ ∠ PRQ = ∠ PST ( Corresponding angle )
∴ Δ RQP ≅ Δ TSP ( BY ASA RULE )
Now ,
⇒ X = 3
<h2>○=> <u>Correct option</u> :</h2><h2>
</h2><h3>○=> <u>Steps to derive correct option</u> :</h3>
We know that :
So, let the diameter of this circle be x.
Which means :
Thus, the radius of the circle Robert drew = 6 m
Since the circle in option B has a radius of 6 m, it is the circle Robert drew.
▪︎<em>Therefore, the correct option is (B)</em>