PLEASE PLEASE PLEASEE PLEASEEEEESE HELPME!?!?!? IM SO BAD AT MATH PLEASE HELP!!!

1 answer:

7 0

For this case we have the following function:
$f (x) = 0.01 * (2) ^ x
$
By definition, the average rate of change is given by:
$AVR = \frac{f(x2) - f(x1)}{x2 - x1}$
We evaluate the function for the given values:
For x = 7:
$f (7) = 0.01 * (2) ^ 7

f (7) = 1.28$
For x = 14:
$f (14) = 0.01 * (2) ^ {14} f (14) = 163.84$
Then, replacing values we have:
$AVR = \frac{163.84 - 1.28}{14 - 7}$
$AVR = 23.22$
Answer:
the average rate of change from x = 7 to x = 14 is:
a. 23.22

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$\bf \begin{cases}
(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12
\\
&\qquad \uparrow \\
&\textit{same bases, thus}\\
&\qquad \downarrow 
\\
n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6
\end{cases}
\\\\\\
thus\implies 
\begin{cases}
4p=12\implies p=\frac{12}{4}
\\\\
3+q=6\implies q=6-3
\end{cases}
\\\\

\\\\
then\implies p\cdot q=\boxed{?}$