I) if the triangles are similar then the corresponding angles are congruent. this means that the angles are of the same size.
ii) If ΔABC is similar to ΔDEF, therefore; m∠A = m∠D, m∠B=m∠E, and m∠C=m∠F,
thus, if m∠A= 52, m∠D=52, and if m∠E=65, then m∠B=65, thus to get m∠C;
180- (52+65)
= 63 , therefore; m∠C= 63
iii) if two figures are similar they have the same shape and not necessarily the same size while if two figures are congruent then they have the same shape and size
Answer:
slope = 5
Step-by-step explanation:
The equation of a lin in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 5x + 3 ← is in slope- intercept form
with slope m = 5
Parallel lines have equal slopes , then
The slope of a line parallel to y = 5x + 3 is 5
Answer:
Step-by-step explanation:
5/8 + 3/5 =
25/40 + 24/40 =
49/40 = 1 9/40
its greater then 1
we have
y > -2
x + y < 4
using a graph tool
see the attached figure
The shaded area is the solution of the system
<u>Part 1) </u>Name an ordered pair that is a solution to this system and explain how you know that this is a solution point
Let
A ( -40,20)
The point A is solution of the system because the point lie on the shaded area
<u>Check</u>
If the point A is solution of the system must satisfy both system inequalities
point A
x=-40
y=20
substitute
y > -2-------> 20 > -2-------> is ok
x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok
therefore
<u>the answer Part 1) is</u>
The point A is a solution of the system
Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution
Let
B(20,20)
The point B is not solution of the system because the point not lie on the shaded area
<u>Check</u>
If the point B is not solution of the system must not satisfy both system inequalities
point B
x=20
y=20
substitute
y > -2 -------> 20 > -2-------> is ok
x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok
therefore
<u>the answer part 2) is</u>
The point B is not a solution to the system
Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
__
Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
