Answer:
17.1 degrees
Step-by-step explanation:
This is a tangent question because angle XYZ is adjacent to 13 and opposite of 4. This means that we will have to use opposite/adjacent. This is very simple if you know the formula. Just plug those numbers in to get 4/13 = 0.3076923076923077. However, now we need to find it in degrees. If you have an inverse calculator near you, you would plug it in to get about 17.10, which rounds to 17.1.
A point is an abstraction to point a location or vertex (intersection of lines). It has no size. Consequently it does not have shape or color or any physical characteristic.
Then the answer is all of the above.
Answer: y=-3/4x-2
Step-by-step explanation:
Write an equation of a line in slope-intercept from with the given slope, slope:–3/4, y-intercept: –2
The y-intercept is at (0,-2)
Then we write the equation using y=mx+b becuase that is the point slope form.
m=-3/4 which was given in the question
because y-intercept is at (0,-2)
y=-2
x=0
-2=-3/4(0)+b
-2=0+b
-2=b
now we know that m is -3/4 and b is -2
Hence the equation is y=-3/4x-2
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
Y=-4/2 + 6
Step-by-step explanation:
It is +6 because the line intercepts the Y axis at the point 6. It is a negative slope. It is a slope of -4/2 because from point (0,6) it goes down 4 and 2 right.
