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Rufina [12.5K]
4 years ago
14

In Lisa’s class 24 of the students are tall and 12 are short in Paul’s class 15 students are tall and 20 students are short whic

h class has a higher ratio of tall to short students?
Mathematics
2 answers:
xxTIMURxx [149]4 years ago
7 0
Lisa= 24:12= 2:1
paul= 15:20= 3:4
lisa= 8:4 paul= 3:4
lisa’s class has a higher ratio of tall to short people
artcher [175]4 years ago
6 0

Answer:

Lisa’s

Step-by-step explanation:

Ratio- Tall:Short

Lisa’s Class- 24:12

Paul’s Class- 15:20

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Answer:

3y = -2x -7

Step-by-step explanation:

The equation of the line;

     y = -\frac{2}{3}x + 8

Unknown:

Equation of the line passing through (4, -5);

Solution:

To solve this problem;

    the equation of a line is given as;

        y = mx + c

where x and y are the coordinate

           m is the slope

          c is the intercept

To solve this problem,

  The slope  -\frac{2}{3} if the same as that of the new line since they are parallel;

Equation of the new line;

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    y =  -\frac{2}{3}x - \frac{7}{3}

 or ;

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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

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b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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3 years ago
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