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Rzqust [24]
3 years ago
12

A regular heptagon has sides measuring 26mm and is divided into 7 congruent triangles. Each triangle has a height of 27mm. What

is the area of the heptagon?
Mathematics
1 answer:
Yuri [45]3 years ago
6 0
The area of any regular polygon when a side length is know is just:

A(s,n)=ns^2/(4tan(180/n))  in this case:

A(26, 7)=(7*26^2)/(4tan(180/7))

A(26, 7)=2456.5 mm^2 to nearest tenth of a mm^2
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Identify the solution to the following inequality: -1/2 (x+3) > x - 3
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A

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P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Mila [183]

Answer:

The polynomial is:

p(x) = -x^3 - 2x^2 + 5x + 6

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that x_1 = -3, x_2 = -1, x_3 = 2. Thus

p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)

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p(x) = a(x^2+4x+3)(x-2)

p(x) = a(x^3+2x^2-5x-6)

Passes through the point (1,12).

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