A regular heptagon has sides measuring 26mm and is divided into 7 congruent triangles. Each triangle has a height of 27mm. What
is the area of the heptagon?
1 answer:
The area of any regular polygon when a side length is know is just:
A(s,n)=ns^2/(4tan(180/n)) in this case:
A(26, 7)=(7*26^2)/(4tan(180/7))
A(26, 7)=2456.5 mm^2 to nearest tenth of a mm^2
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