Dilation by a factor of 3 about the origin multiplies each coordinate by 3. To find what was multiplied by 3 to get the given coordinates, we divide the given coordinates by 3.
Given: <span>2x-y-3=0. find </span>equation for the line perpendicular to the given line that goes through the given point:<span> (2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span> => (x-0)/2=(y-4)/-1 (</span>canonical <span>equation) =>x+2y-8=0(general </span><span>equation) </span> <span>further: {x+2y-8=0 {2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line </span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
