Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Answer:
19 28/33
Step-by-step explanation:
lets work out the whole number parts first:
= 19 + 17 - 16 = 20.
4/12 + 2/11 - 6/9
= 1/3 + 2/11 - 6/9
Find the LCM of the denominators:
3 = 3
11 = 11
9 = 3*3
- so the LCM is 3*3*11 = 99.
So we have:
33/99 + 18/99 - 66/99
= 51/99 - 66/99
= -15/99
= -5/33
So the answer is 20 - 5/33
= 19 28/33
You just had to subtract 5/33 from 20.
It’s 28!!, good luck on whatever your doing
To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
