Answer:
the second answer seems to be the most reassonable
Step-by-step explanation:
Answer:
S(-2, -3)
Step-by-step explanation:
Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;
S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;
x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1
Substitute the values into the formula;
X = ax2+bx1/a+b
X = 3(-1)+1(-5)/3+1
X = -3-5/4
X = -8/4
X = -2
Similarly;
Y = ay2+by1/a+b
Y = 3(-5)+1(3)/3+1
Y = -15+3/4
Y = -12/4
Y = -3
Hence the coordinate of the point (X, Y) is (-2, -3)
Answer:
40 cm
Step-by-step explanation:
Perimeter of a square = 4a
=4 ( 10 )
=40cm
Have a nice day!
First you need to find the volume of the cylinder. Then find the volume of all 4 rubber balls (spheres). Subtract the cylinder's volume by the spheres' volumes.
Volume of cylinder: πr²h
π2.5²(20) = 392.7 cm³
Volume of sphere: 4/3πr³
4/3π2.5³ = 65.45 cm³
392.7 - 65.45 = 327.25
The amount of space in the container unoccupied by the rubber balls is 327 cm³.
<h3>
ax² + bx + c = 0</h3>
<em>Let's write -9 where we see A</em><em>:</em>
<h3>
-9x² + bx + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>
<h3>
-9x² + 0.x + c = 0</h3>
<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>
<h3>
-9x² + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>
<h3>
-9x² + -2 = 0</h3>
<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>
<em>Let's put the known and the unknown on different sides:</em>
<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>
<h3>
-9x² = 2</h3>
<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<h3>
x² = 2/-9</h3>
<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>
<em>Please do not report</em><em>:</em><em>(</em>
<em>I hope I got it right, I'm trying to improve my English a little :)</em>
<h3>
<em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>
<h3>
<em><u>#XBadeX</u></em></h3>