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ss7ja [257]
3 years ago
15

and Equipment safety test requires five independent tests. Each of these test has a 78% pass rate. The equipment will only be gi

ven a positive safety rating if it passes all five tests. Find the probability of equipment receiving a positive rating.
Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
The probability that the equipment will receive a positive rating and pass all five tests is approximately 28.89%
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A tunnel must be made through a hill. As a result, a surveyor and an engineer create a sketch of the area. The sketch, displayed
Anastasy [175]

Answer:

498 m

Step-by-step explanation:

The AAA theorem states that triangles are similar if all three corresponding angles are equal.

1. Compare triangles FHS and ILS

(a) Reason for similarity

∠F = ∠I = 90°

∠S is common.

∴ ∠H = ∠L

(b) Calculate SL

\begin{array}{rcl}\dfrac{SF}{SH} & = & \dfrac{SI}{SL}\\\\\dfrac{225}{380} & = & \dfrac{225 + 475}{SL}\\\\225SL & = & 380 \times 700\\& = & 266000\\SL & = & \textbf{1182 m}\\\end{array}

2. Compare triangles ILS and GLE

(a) Reason for similarity

∠I = ∠G = 90°

∠L is common.

∴ ∠S = ∠E

(b) Calculate LE

\begin{array}{rcl}\dfrac{IS}{GE} & = & \dfrac{LS}{LE}\\\\\dfrac{700}{180} & = & \dfrac{1182}{LE}\\\\700LE & = & 180 \times 1182\\& = & 212800\\LE & = & \textbf{304.0 m}\\\end{array}

3. Calculate EH

               LE + EH + HS = LS

304.0 m + EH + 380 m = 1182 m

                  EH + 684 m = 1182 m

                                 EH = 498 m

The distance from E to H is 498 m.

 

5 0
3 years ago
8× what =2
sergejj [24]

Answer:

8*1/4= 2

A) 0.071

B) 0.48

5 0
3 years ago
Select all the equations where m = 4 is a solution.
Aneli [31]
The answers are A,B, and E. Hope this helps. :)
4 0
3 years ago
GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
3 years ago
8/3 × (−2 1/2) = ?<br><br><br>Thanks!
Veronika [31]

Answer: -20/3

Step-by-step explanation:

4 0
3 years ago
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