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AURORKA [14]
2 years ago
5

ASAP options: leftrightup down​

Mathematics
1 answer:
Alenkinab [10]2 years ago
5 0
Right 6 and down 5 hope this helps you out
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7 0
2 years ago
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The original price of a measuring tape is $4.30. How much will Hector pay if he buys it during the sale?
Murrr4er [49]

Answer:

how much percent is off?

Step-by-step explanation:

8 0
2 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
How tall is the welcome sign​
lisov135 [29]

Answer:

the sign is 5 ft tall

Step-by-step explanation:

30 % 12.5=2.4

12 % 2.4=5

4 0
3 years ago
A computer training institute has 625 students that are paying a course fee of $400. Their research shows that for every $20 red
Anastasy [175]
1.
If no changes are made, the school has a revenue of :

625*400$/student=250,000$

2.
Assume that the school decides to reduce n*20$.

This means that there will be an increase of 50n students.

Thus there are 625 + 50n students, each paying 400-20n dollars.

The revenue is: 

(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)

3.

check the options that we have, 

a fee of $380 means that n=1, thus 

250(n+50)(20-n)=250(1+50)(20-1)=242,250   ($)


a fee of $320 means that n=4, thus

 250(n+50)(20-n)=250(4+50)(20-4)=216,000    ($)


the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.

Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
6 0
3 years ago
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