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Akimi4 [234]
3 years ago
7

I dont understand these problems |×| - 1 < 5 , 3x + 4 <-2, 5x/7 -2=1, 9(2x+3)=10

Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0
|x|-1
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Write a polynomial function of the least degree that has roots of 3 and (4 + i).
polet [3.4K]

Answer:

  • x³ - 11x² + 41x - 51

Step-by-step explanation:

The least number of degree is 3 and the third root should be (4 - i) to make polynomial rational.

<u>The polynomial is:</u>

  • (x - 3)(x - (4 + i))(x - (4 + i)) =
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6+3(x+4)=24. solve the following equation please ​
Evgen [1.6K]

Answer:

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Step-by-step explanation:

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2 years ago
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Sophie [7]

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3 years ago
A diameter of a circle has enpoints (-2, 10) and (6, -4) in the standard (x, y) coordinate plane. What is the center of the circ
wlad13 [49]

Answer:

The center of the circle is C(x,y) = (2, 3).

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y) (1)

Where:

C(x,y) - Center.

R_{1} (x,y), R_{2} (x,y) - Location of the endpoints.

If we know that R_{1} (x,y) = (-2,10) and R_{2} (x,y) = (6,-4), then the location of the center of the circle is:

C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)

C(x,y) = (-1, 5) + (3, -2)

C(x,y) = (2, 3)

The center of the circle is C(x,y) = (2, 3).

8 0
2 years ago
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