All categories

3 years ago

How much does a puzzle piece weigh

2 answers:

6 0

It depends on the size. For example, A standard 500-piece puzzle is approximately 19 inches by 19 inches. Jumbo puzzles with 2,000 to 3,000 pieces could measure as much as 33 inches by 48 inches.<span>
</span>

Rashid [163]3 years ago

5 0

This all depends on the length,and the width.

You might be interested in

Please help me answer this with an explanation

Nata [24]

You need to find the slope first. (-9,-4). (3,4)

-4-4= -8
-9-3 =-12. Slope is -8/-12 or 8/12 or 2/3

Perpendicular is the negative reciprocal. Or flip over the 2/3 and make it negative.

The answer is - 3/2

5 0

3 years ago

Read 2 more answers

ANSWER ASAP

Brums [2.3K]

Answer:

y = 2x + 3
y = -6x
y = -x + 2
y = 2x - 7

Step-by-step explanation:

<u>Slope-intercept form:</u>

y = mx + b

<em>Hint. if we have x = 0, then the y-coordinate is the same as b</em>

<u>Slope</u>

m = (y2 - y1)/(x2-x1)

33.

m = (9 -(-3))/(3 - (-3)) = 12/6 = 2
b = 3 as per table (0, 3)

y = 2x + 3

34.

m = (0-12)/(0 - (-2)) = -12/2 = -6
b = 0, as per table (0, 0)

y = -6x

35.

m = (2 - (-2))/(0 - 4) = 4/-4 = -1
b = 2, as per table (0, 2)

y = -x + 2

36.

m = (-5 - (-1))/ (1 -3) = -4/-2 = 2

Using point (3, -1)

-1 = 2*3 + b
b= -1 - 6= - 7

y = 2x - 7

8 0

3 years ago

What is the 138-20+15

nlexa [21]

Then answer you seek is 133.

5 0

3 years ago

Express 2.7 as a fraction of 3.6 giving your ansver as a fraction<br> in its lowest terms.

MakcuM [25]

2.7 is 27/10 and 3.6 is 18/5

3 0

2 years ago

Find the value of x for which the function y = x5-x³ + x² - 1 has a local minimum.

melisa1 [442]

The given function presents a local minimum in the coordinates (0,-1).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

For solving this question, the given equation should be rewritten from the factoring.

$x^5-x^3+x^2-1=\left(x+1\right)^2\left(x-1\right)\left(x^2-x+1\right)=0$ . Then, you have 3 equations.

From the Zero Factor Principle, you can write

Equation 1

(x+1)²=0

x+1=0

x= -1

Equation 2

x-1=0

x=1

Equation 3

x²-x+1=0

$x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\ \\ x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{3}i}{2\cdot \:1}$

From these points it is possible to plot a graph and you can see that the local minimum presents the coordinates (0,-1).