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andreev551 [17]
3 years ago
14

PLEASE HELP ASAP! Which equation is represented by the graph below? y=e^x+5 y=e^x+4 y=ln x+4 y=ln x+5

Mathematics
2 answers:
Ronch [10]3 years ago
8 0

Answer:

y = ln(x) + 4

Step-by-step explanation:

Fastest way to do this is to graph each equation into a graphing calc and match it with the given graph.

lukranit [14]3 years ago
8 0

Answer:

y = ln x+4

Step-by-step explanation:

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find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times
Vlad1618 [11]

Answer:

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Step-by-step explanation:

7 0
3 years ago
I need help ASAP <br> 120&gt;10n+20
Burka [1]

Answer:n = 10 can make the inequality true

Step-by-step explanation:

The given inequality is

120 greater than or equal to 10n + 20. This means that the least value of n that would make the inequality true would be 10.

If we substitute n = 10 into the right hand side of the given inequality, it would result to 120.

So n = 10 can make the inequality true.

4 0
3 years ago
I really need help its 7th grade math1!
Gelneren [198K]
ANSWER:
graph y = 4x - 12 (use desmos graphing calc if needed)
EXPLANATION:
y = mx + b
y = 4x + b
0 = 4(3) + b
0 = 12 + b
-12 = b
y = 4x - 12
3 0
3 years ago
Noah bought 1/2 pound of candy to share with his friends.They ate 3/8 pound of the candy.How much candy does Noah have left?
murzikaleks [220]
You need common denominators so change 1/2 to 4/8
then 4/8-3/8=
1/8 of a pound left 
3 0
3 years ago
Read 2 more answers
Which of the following events has an expected value that is in the sample space? A. tossing a number cube once B. flipping a coi
neonofarm [45]

A) The event is "tossing a number cube once"

The sample space of this event is {1,2,3,4,5,6}.

The expected value of this event is  

1\times \frac{1}{6}+2\times \frac{1}{6}+3\times \frac{1}{6}+4\times \frac{1}{6}+5\times \frac{1}{6}+6\times \frac{1}{6}\\ \\ =\frac{1}{6}+\frac{1}{3}+\frac{1}{2}+\frac{2}{3}+\frac{5}{6}+1\\ \\ =\frac{7}{2} = 3.5

Since 3.5 is not in the sample space of the event. Therefore, option (A) is not correct.

(B) The event is "Flipping a coin"

Sample space of this event is {HH,TT,HT,TH}

Since sample space of this event is not numbers, therefore, this cannot be the correct option either.

(C) The event is, "Randomly picking a number between 1 and 9, inclusive."

The sample space of this event is {1,2,3,4,5,6,7,8,9}.

Expected value of this event is \frac{1}{9}(1+2+3+4+5+6+7+8+9) = \frac{1}{9}(45) = 5

Since 5 is the expected value and it is present in the sample space for this event. Therefore, option (C) is a correct choice.

(D) The sample is "Randomly picking a number between one and ten, inclusive".

The sample space of this event is {1,2,3,4,5,6,7,8,9,10}.

Therefore, expected value of the event is \frac{1}{10}(1+2+3+4+5+6+7+8+9+10) = \frac{1}{10}(55)=5.5

Since 5.5 is not present in the sample space of this event. Therefore, option (D) is not correct either.

Hence, the correct choice is option (C).


4 0
3 years ago
Read 2 more answers
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