Question

The length of a rectangle is 8 in. more than its width. The perimeter is 52 in. What is the length of the rectangle?

Answer 1

$L=w+8 \\\\ P=2L+2w \\ P=52in \\\\ 2(w+8)+2w=52 \\\\ 2w+16+2w=52 \\\\ 4w=52-16 \\\\ 4w=36 \\\\ \boxed{w=\frac{36}{4}=4in} \\\\ L=4+8 \\\\ \boxed{L=12in}$

Answer 2

It would be 17 for the length
And 9 for the width