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Andreas93 [3]
4 years ago
15

I NEED HELP HURRY PLEASE, THANKS! :)

Mathematics
2 answers:
Natalija [7]4 years ago
8 0

Answer:  \bold{b)\quad \dfrac{\pi}{2}+n\pi,\ \dfrac{\pi}{4}+2n\pi}

<u>Step-by-step explanation:</u>

cos x tan x - cos x = 0

cos x (tan x - 1) = 0

cos x = 0          tan x - 1 = 0

x=\dfrac{\pi}{2},\ \dfrac{3\pi}{2}         tan x = 1

                         x=\dfrac{\pi}{4},\ \dfrac{5\pi}{4}

Alenkasestr [34]4 years ago
7 0

Thanks! I hope my answer would be easy to understand.

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2) A circle has an area of 121 ñ cm. Find its circumference. (Round your answer to the
crimeas [40]

Answer:

If the area is 121 cm the answer is 38.99 if its 12 cm then the answer is 12.28

Step-by-step explanation:

Im not sure if correct but i tried

7 0
3 years ago
A wheelchair access ramp has an angle of elevation of 41 degrees. If the ramp reaches to the top of a 26 inch high porch, how lo
Gemiola [76]

Answer:

HAHA THAT DISABLED F-WORD

Step-by-step explanation:

7 0
4 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
The senior classes at High School A and High School B planned separate trips to the indoor climbing gym. The senio class at High
Mariana [72]
Let x person in 1 van and y persons in 1 bus
 so for school  A  took    2x+2y=106
for school  B  took    8x+y=151

make a system
\left \{ {{2x+2y=106} \atop {8x+y=151}} \right.
solve it:
multiply second equation by 2
<span> 2*8x+2*y=2*151</span>
16x+2y=302

second equation minus first we have:
16x+2y-2x-2y=302-106
14x=196
x=14 - persons in 1 van

to find y put x=14 in equation:
2x+2y=106
2*14+2y=106
2y=106-28
2y=78
y=39
Answer:  1 van can carry 14persons, 1 bus can carry 39 persons







5 0
3 years ago
Round 5,762.384 to the nearest ten
swat32
If it's nearest ten then it would be 5,760. If anything is 4 or lower than the number, like 74, then it would be 70. 
If it was 5 or higher, like 37, then it would become 40.
Hope this helps! :) 
7 0
3 years ago
Read 2 more answers
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