Answer:
The statements that must be true are:
XY and JK form four right angles ⇒ B
XY ⊥ JK ⇒ C
JP = KP ⇒ E
m∠JPX = 90° ⇒ F
Step-by-step explanation:
From the given figure
∵ Line XY is the perpendicular bisector of the line segment JK
→ That means line XY is the line of symmetry of the line segment JK
∴ XY ⊥ JK ⇒ C
∵ XY ∩ JK at point P
∴ P is the midpoint of JK
∵ XY ⊥ JK
∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles
∴ XY and JK form four right angles ⇒ B
∵ The measure of the right angle is 90°
∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°
∴ m∠JPX = 90° ⇒ F
∵ P is the midpoint of JK
∴ JP = KP ⇒ E
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Simplify</u>
- Distribute:
- Multiply:
- Rearrange:
- Combine like terms:
Answer:
11:3
Step-by-step explanation:
For every 11 y there is 3x
Answer:
-15
Step-by-step explanation:
We proceed as follows;
In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.
Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.
Thus, we have;
2a(b-3) + 5b + _
Now, putting -15 will give us the same expression in the first bracket and this gives us the following;
2a(b-3) + 5b-15
2a(b-3) + 5(b-3)
So we can have ; (2a+5)(b-3)
Hence the constant used is -15
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