The graph should be discrete, even though often times you will see it graphed as continuous only because the graphing software used might not have the capability of showing discrete dots rather than continuous lines. Basically you can only sell whole tickets , so that makes the value of x integers .
the fact that y is not an integer is irrelevant.
in fact, y is also restricted in the values it can take.
those values are determined by the factor of 2.50 * x.
when x = 0, y = 0 * 2.50 = 0
when x = 1, y = 1 * 2.50 = 2.50
when x = 2, y = 2 * 2.50 = 5.00
when x = 3, y = 3 * 2.50 = 7.50
when x = 4, y = 4 * 2.50 = 9.00
the values of y can only be multiplies of 2.50.
the equation used is y = 2.50 * x
x is the number of tickets sold.
Answer:
73.33% probability that they also took the SAT
Step-by-step explanation:
We have these following two events.
Event A: Taking the ACT exam. So P(A) = 0.3.
Event B: Taking the SAT exam. So P(B) = 0.37.
The conditional probability formula is:
![P(B|A) = \frac{P(A \cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28B%29%7D)
In which P(B|A) is the probability of event B happening given that A has happened,
is the probability of both events hapenning.
22% of graduating seniors too both exams.
This means that ![P(A \cap B) = 0.22](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.22)
If the student took the ACT, what is the probability that they also took the SAT?
![P(B|A) = \frac{P(A \cap B)}{P(B)} = \frac{0.22}{0.3} = 0.7333](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28B%29%7D%20%3D%20%5Cfrac%7B0.22%7D%7B0.3%7D%20%3D%200.7333)
73.33% probability that they also took the SAT
Answer:
Undefined
Step-by-step explanation:
Use the formula:
y2 - y1/x2 - x1
8 - (-3)/5 - 5
8 + 3/0
11/0
Undefined
a) x = 77 degrees
b) B - alternate angle
(The angle that shows 'Z' shape is alternate as both the angles are equal)
Respuesta:
1,4 kilometros
Explicación paso a paso:
Dado que :
Distancia que separa a Sandra y José en el mapa = 7cm
Dibujo a escala = 1: 20.000; Esto se puede interpretar en el sentido de que 1 cm en el mapa equivale a 20.000 cm en el suelo.
Por tanto, una distancia de 7 cm en el mapa será:
20.000 * 7 = 140.000 cm en el suelo = distancia real
Por lo tanto, la distancia real = 140.000 cm.
Recordar :
1 cm = 10 ^ -5 km
140000 cm = 1.4 kilometros
Por lo tanto, la distancia real entre Sandra y José es de 1,4 km.