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Taya2010 [7]
3 years ago
7

a boat costs 11,850 and decreases in value by 10% per year. how much will the boat be worth after 8 years

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
If the boat initially cost $11850 and INCREASED in value by 10% per year, we'd calculate the final value like this:

V = $11850(1+0.10)^8

But if the boat is losing value (depreciating) over time, we'd calculate its final value like this:

V = $11850(1-0.10)^8  =  $11850(0.90)^8 = $11850(0.4305) = $5101.04 (answer)
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(a + b - c )(a + b + c )
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If you are looking for the expanded version, this is it. It is also possible to group either an a from (a^2 + 2b) or a b from (2ab + b^2). Hope this helps!

6 0
3 years ago
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Points Possible: 1, Points Correct: 0 Given the equation y = x + 9, what is the y -intercept?
-Dominant- [34]

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9

Step-by-step explanation:

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3 years ago
A survey asked people of different ages whether they get their news by reading the paper. What is the probability that a person
Bingel [31]

C. 60%

The probability that a person surveyed is 40 or older and gets the news by reading the paper is 60%.

Step-by-step explanation:

In our case, we have to find the probability of a person getting their news by reading the paper. But we are given with a condition that the person must be 40 or older.

The survey is conducted among 80 people.

Number of people aged 40 or older = 40

No of people aged 40 or older and read paper = 24

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Probability of a person aged 40 or older reads a paper =

(No. of People aged 40 or older and read paper)/(No. of people aged 40 or older)

= 24/40

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3 years ago
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What makes a function
Bas_tet [7]
A function is a expression that defines a relationship between one variable and another variable
4 0
3 years ago
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Please help asap!!!!!!
RSB [31]

Answer:

z = 66

Step-by-step explanation:

QT is a midsegment. Thus, applying the midsegment theorem:

RS = 2(QT)

QT = z - 33,

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Plug in the values into the equation

z = 2(z - 33)

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Subtract 2z from each side

z - 2z = -66

-z = -66

Divide both sides by -1

z = 66

5 0
2 years ago
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