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Nesterboy [21]
2 years ago
6

It’s timed please help

Mathematics
1 answer:
love history [14]2 years ago
6 0

Answer:

4 is included in the domain

Step-by-step explanation:

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Will give brainliest to whoever answers both questions!! I need to turn this in soon!
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Answer:

y=55x

given y=385

x=gallons of gas = 385/55 = 7 gallons

inverse function

y=55x

change x to y and y to x

x=55y

y=x/55

inverse function is x/55

Step-by-step explanation:

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At a car garage there are 100 vehicles, 60 of which are cars, 30 are vans and the remainder are
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there are 10 of the other kind of cars

Step-by-step explanation:

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3 years ago
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Amy has a garden covering 900 square feet.
blagie [28]
A.900/10=90 therefore, 10% of the garden will be covered moss roses so that transfers to 90 square feet

B.900 square feet is equal to 25% of the garden so 900x4=3600 therefore, the area of the yard in square feet could either be 30x120, 60x60, or 180x20
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217.72 million in scientific notation
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2.17720 × 10^2 is the answer

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3 years ago
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
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