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juin [17]
3 years ago
7

Mary was asked to find the slope of the line 3x - 4y = 12. She says the answer is 3/4

Mathematics
1 answer:
Vinvika [58]3 years ago
7 0

The correct answer is D. Choose two points on the graph and count the rise and the run between them. Graph D is the only one that also has a slope of  3/4 .

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A large university accepts 70% of the students who apply. Of the students the university accepts 25% actually enroll if 20,000 s
Andru [333]

Answer:

3500 students actually enroll

Step-by-step explanation:

20000*0.7*.25=3500

6 0
3 years ago
Read 2 more answers
Write the equation of a line in slope intercept form that contains the points (0,2) and (3,4)
AlladinOne [14]

Answer:

Step-by-step explanation:

Generally equation of a line is given as

y=mx+c

Then given the point (x, y)=(0,2)

Therefore x=0 and y=2

y=mx+c

2=m×0+c

2=0+c

Then, c=2

Then intercept is 2

Also given the point (x, y)=(3,4)

x=3 and y=4 and c=2

y=mx+c

4=m×3+2

4=3m+2

4-2=3m

2=3m

Then, m=2/3

Then, the slope of the graph is 2/3

y=mx+c

Now, m=2/3 and c=2

The general equation of the line becomes

y=2/3x+2

Multiply through by 3

3y=2x+6

Then this is the equation of the line

6 0
3 years ago
Given the equation 4X +7 = 3 (2x -5 ) solve for the variable explain each step in justify your process
alexandr1967 [171]

Answer:

x = 11

Step-by-step explanation:

4x + 7 = 6x -15

4x - 6x = -15-7

-2x = -22 / : (-2)

x = 11

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

5 0
3 years ago
Please look at the image which includes the question ! I need help on this. I am pretty confused right now.
vlabodo [156]
I'm guessing it's (8,9)
5 0
3 years ago
Line a and b are perpendicular lines.If line a is represented by y=s/t x+10 and line b is represented by y=q/r -4 where s,t,q an
alekssr [168]

Answer:

The options are not shown, so i will answer in a general way.

First, for a line of the form:

y = a*x + b

All the perpendicular lines will have a slope of -(1/a), then we can write a general perpendicular line as:

y = -(1/a)*x + c.

In this problem we have the perpendicular lines:

y=(s/t)*x+10

y = (q/r)*x - 4

Because those lines are perpendicular, we must have that:

(q/r) = -(1/(s/t)) = -(t/s)

q/r = -t/s

and we knew that s, t, q and r are integers (where t and r can not be equal to zero), and because of this relation, where we can see that in the denominator at the right we have the integer s, we can conclude that s can not be zero (we can not divide by zero).

And we know that t and s are both different than zero, then:

-t/s ≠ 0.

This means that:

q/r ≠ 0

And from this, we can conclude that q is different than zero.

7 0
3 years ago
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