15,17,19
Suppose the three odd integers are #n#, #n+2# and #n+4#
Their sum is:
#n + (n+2) + (n+4) = 3n+6#
#13# more than twice the largest of the three is:
#2(n+4)+13 = 2n+21#
From what we are told these two are equal:
#3n+6 = 2n+21#
Subtract #2n+6# from both sides to get:
#n = 15#
So the three integers are:
#15, 17, 19#
Answer:
35
Step-by-step explanation:
Answer:
as the cycle continues, you will always get 50 as the answer, since you are dividing both the numerator and the denominator with 10 in each expression. In other words, the 10:00 you divide the numerator which cancels out with the 10 you divide the denominator with. So the answer will always be 50 in each next expression.
Step-by-step explanation:
(I) 45÷90= 4500/90 = 50
(ii) 450÷9= 450/9 =50
(iii) 45÷0.9 = 45/0.9=50
(iv) 4.5 ÷ 0.09 = 45/0.09
starting with (I) 4500÷90 = 4500/90 =50
you divide the numerator and the denominator by 10 to get ; (ii) 450÷9 = 450/9 = 50
as the cycle continues you will always get 50 as the answer since you are dividing both the numerator and the denominator with 10 in each expression. In other words, the 10:00 you divide the numerator with cancels out with the 10 you divide the denominator with. So the answer will always be 50.
Answer:
-58
Step-by-step explanation:
-7*8 = -56
So -56/8= -7
But we have a +2 there, so do the opposite. So -56-2. is -58.
(-58+2) / 8 = -7
