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3 years ago

If the leg of a triangle is 48 and the hypotenuse is 60 what is the length of the other leg

Mathematics

1 answer:

AURORKA [14]3 years ago

4 0

Answer:

The length of the other would be 36.

Step-by-step explanation:

a² + b² = c²

b² = c² - a²

b² = 60² - 48²

b² = 3600 - 2304

b² = 1296

√b² = √1296

b = 36

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3 years ago

Mary runs 5 miles in 1.25 hours. How many miles does she run in 1 hour? HELP PLSSS

ICE Princess25 [194]

Answer:

She runs 4 miles in one hour

Step-by-step explanation:

5 divided by 1.25=4

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3 years ago

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3 years ago

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

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2 years ago

To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the

natta225 [31]

Answer: We should reject the null if the test statistic is greater than 1.895.

Step-by-step explanation:

We assume the population to be normally distributed.

Given: Sample size : $n=8$ , which is asmall sample (n<30), so we use t-test.

We always reject the null hypothesis if the absolute t-value is greater than critical value.

Therefore, We should reject the null if the test statistic is greater than 1.895.

3 0

2 years ago