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VikaD [51]
3 years ago
14

Solve for x: 1/8-2/×=5someone pls help me ASAP

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
Begin by subtracting 1/8 from both sides to get - \frac{2}{x} =5- \frac{1}{8} and get a common denominator of 8 on the right:- \frac{2}{x} = \frac{40}{8} - \frac{1}{8}.  Now simplify and cross-multiply: 39x = -16 andx = -16/39

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Please help asap!
allochka39001 [22]

Answer:

  See below

Step-by-step explanation:

The solution choices all agree that x = 1±√2. The second equation tells you ...

  y = ±2√(x+2)

so the sign of the √2 term in x is the same as the sign of the √2 term in y. The answer choices circled in red are the ones that meet this requirement.

4 0
3 years ago
A man's basic wage for a 40-hour week
Mashcka [7]

Answer:

467.50

Step-by-step explanation:

do 61.5 times 5 to get 307.5 and add to 160 to get 467.50

6 0
3 years ago
Read 2 more answers
If the first chapter of a certain book is 16 pages long and makes up 4% of the book, how many pages does the entire book have?
galina1969 [7]
If 16 pages equal to 4%, how many pages will equal to 100%?

4/100 = 16/x
4x=1600
X= 400

So total pages should be 400.
5 0
2 years ago
2. Which expression is equivalent to 5(n + 3) - 10? A. 5+1 +5+3 – 10 B. 5 • n + 5 + 3 - 10 C. 5. n + 5 • 3 – 10 D. 5 • n • 5 • 3
GuDViN [60]

Answer:

5n+5

Step-by-step explanation:

5(n+3)-10

5n+15-10

5n+5

8 0
3 years ago
Find the inverse of the following matrix without using a calculator 1-1 2 -3 2 1 0 4 - 25
Artist 52 [7]

Answer:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

Step-by-step explanation:

You can solve this problem by using the Gauss-Jordan method.

You have the original matrix and then the Identity matrix.

So:

Original              Identity

1 -1 2                    1 0 0

-3 2 1                   0 1 0

0 4 -25                0 0 1

By the Gauss-Jordan method, in the original place you will have the identity and in the place that the identity currently is you will have the inverse matrix:

So, let's start by setting the first row element to 0 in the second and the third line.

The first row element of the third line is already at zero, so no changes there. In the second line, we need to do:

L2 = L2 + 3L1

So now we have the following matrixes.

1 -1 2        |            1 0 0

0 -1 7       |            3 1 0        

0  4 -25   |            0 0 1

Now we need the element in the second line, second row to be 1. So we do:

L2 = -L2

1 -1 2        |            1 0 0

0 1 -7       |            -3 -1 0        

0  4 -25   |            0 0 1

Now, in the second row, we need to make the elements at the first and third line being zero. So, we have the following operations:

L1 = L1 + L2

L3 = L3 - 4L2

Now our matrixes are:

1 0 -5       |            -2 -1 0

0 1 -7       |            -3 -1 0        

0 0 3       |            12 4 1

Now we need the element in the third line, third row being one. So we do:

L3 = -L3

1 0 -5       |            -2  -1     0

0 1 -7       |            -3  -1      0        

0 0 1       |            4    (4/3) (1/3)

Now, in the third row, we need the elements in the first and second line being zero. So we do:

L1 = L1 + 5L3

L2 = L2 + 7L3

So we have:

1 0 0 |       18  -(17/3)   (5/3)

0 1 0 |       25  (25/3)  (7/3)

0 0 1 |       4    (4/3)     (1/3)

So the inverse matrix is:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

4 0
3 years ago
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