Question

6. Find the slope of AB, given A (3,-1) and B (-1/3, 2) *​

Answer 1

Answer: $-\frac{9}{10}$

Step-by-step explanation:

Just plug these points into the slope formula $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

A: (3,-1) = $(x_{1}, y_{1})$

B: (-1/3, 2) = $(x_{2}, y_{2})$

Now solve.

$\frac{2- (-1)}{-\frac{1}{3} - 3 }$

Simplify the numerator by changing the negative and minus to positive: $2 +1$

This simplifies now to 3.

The denominator needs to be simplified by finding a common denominator.

$-\frac{1}{3} -\frac{3}{1}$

The 3/1 needs to be multiplied by 3 on the top and bottom to get. $-\frac{1}{3} - \frac{9}{3}$

Now with a common denominator we can subtract:  $-\frac{10}{3}$

Now we can put our simplified denominator and numerator back together.

$\frac{3}{-\frac{10}{3} }$

Now KCF, keep change flip.

$\frac{3}{1} *- \frac{3}{10}$

Now multiply across.

$-\frac{9}{10}$

This is the final answer as it cannot be simplified any further.