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patriot [66]
4 years ago
12

What is a key component to participating in a school to work program

Advanced Placement (AP)
1 answer:
AnnyKZ [126]4 years ago
6 0
Is job shadows an option if so that is your answer.

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Agatha Christie was a widely read writer of mysteries.
ankoles [38]
I found this same question and the bolded words were OF MYSTERIES.

Choices given were: 
a) adjective phrase 
<span>b) appositive phrase </span>
<span>c) adverb phrase </span>
<span>d) participle phrase
</span>
The phrase OF MYSTERIES is an A) ADJECTIVE PHRASE. It describes the term writer.


4 0
4 years ago
A key drawback with the use of tests to screen individuals for desirable characteristics is that
DochEvi [55]

Answer:

A key drawback with the use of tests to screen individuals for desirable characteristics is that It is a time-consuming procedure.

It is very important for the employees to know exactly what they must look into and assess the characteristics accurately. This process is very time consuming and takes up a lot of patience and resources to carry the tests.

A study that would need to occur quickly cannot indulge into this testing process because of it being very tedious and time consuming.

3 0
4 years ago
ST+QS=RT what its reason
yan [13]

Answer:

PS = RT, PQ = ST Give?

PQ+QS=PS Segment Addition

ST+QS=RT False - should be ST + QS = PS by Substitution

RS+ST=RT Segment Addition

ST+QS=RS+ST Equal of equals are equal

QS=RS Subtraction Property of Equality

Because of the error in 3 the proof is incorrect, i.e. QS ≠ RS

Explanation:

3 0
3 years ago
Which of the following would be considered anthropogenic impacts on the natural environment?
MrRa [10]

Answer:

D. All of the above.

5 0
3 years ago
What percentage of the area under a normal curve lies within the following boundaries? (use two decimal places)
irina [24]
All you have to do is to find the following from the z-score table:
On the 1st row of the table, you can read the value of z & you complete the value by reading the corresponding horizontal line. However watch out which table you are using & what is requested from you. For example in the following question:

a. Between the mean and a z = 1.27: , if you use a normal table it will give you the value of ==> 0.8990==>89.8%, which is the area from the EXTREME LEFT TO z=1.27., whereas yo have to calculate the area from the mean to
 to z=1.27 0r 0.8990 -.5=0.398 or 39.85 (.5, because you start counting from the mean):
so:
a. Between the mean and a z = 1.27 ==> 39.8%

b. Between the mean and a z = -0.91 ==> 0.31859==>18.31%
c. Between the z scores of -1.84 and 1.39 . In this case you will find the value of each z & you will add up both: for z= -1.84 ==> 0.88482 or 88.48%
d. Between the z scores of -2.58 and 2.58: same as above,==>99.1%
e. Above a z of 1.96 , means from z to the end. The area from the mean to z=1.96 ==> 0.475, what wee need is from this point to the end
that is 0.5-0.475=2.5%
f. Below a z score of -2.58 same as above but -2.58 to the extreme left
for z=-2.58 ==>0.49506 , & below this area==> 0.5-0.49506==> 0.49%
g. Above a z score of -1.72 ==> 95.72%
h. Below a z of 1.96 ==>97.5%


8 0
4 years ago
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