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dimaraw [331]
3 years ago
9

If alpha and beeta are the zeroes of 3x^2-5x-2, then evaluate alpha cube beeta + alpha beeta cube

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0
1 I think is the answer I hop it helped.
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Write the first four terms of the sequence<br><br><br> the rule is: start at 3 1/8, subtract 3/4
adell [148]
3 1/8
2 3/8
1 5/8
7/8 
are the first 4 terms.
7 0
3 years ago
Brenda school is selling tickets to a spring musical on the first day of ticket sales for school so three senior citizen tickets
MrRa [10]

Answer:

senior citizen cost $4

children cost $7

Step-by-step explanation:

The question is not complete

<em>Brenda's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen tickets and 9 child ... The school took in $67.00 on the second day by selling 8 senior citizen tickets and 5 child tickets. What is the price each of one senior citizen ticket and one child ticket?</em>

Given data

let senior citizens be x

and children be y

so

3x+9y= 75--------------1

on the second day

8x+5y= 67------------2

solve 1 and 2 above

3x+9y= 75     X8

8x+5y= 67      X3

 24x+72y=600

-24x+15y=201

   0x+57y= 399

divide both sides by 57

y= 399/57

y= $7

put y= 7 in eqn 1 above

3x+9*7= 75

3x+63= 75

3x=75-63

3x=12

x= 12/3

x= $4

7 0
3 years ago
Hey Guys!
zaharov [31]
<h3>Answer: D)  -3</h3>

Explanation:

Recall that y = f(x) since both are outputs of a function.

If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.

On the other hand, if k = -3, then f(x) = -3 has three different solutions. This is because the horizontal line through -3 on the y axis crosses the cubic at 3 different intersection points.

7 0
2 years ago
Read 2 more answers
Simplify<br> PLZ HELP QUICKLY
elena-14-01-66 [18.8K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible val
Dvinal [7]

Let width be W


Then length = 5W

P=2L+2W

P< 96cm

Then the Perimeter  of the rectangle is equal to

(2L+2W)< 96

2*(5W)+2W)≤96


Therefore, 2w+2⋅(5w)≤96


should be your answer


8 0
3 years ago
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