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2 years ago

I just need to make sure this is correct for a test 6x² - 3x when x=5. my answer was 135

Mathematics

2 answers:

Allushta [10]2 years ago

7 0

Answer:

135 is the correct answer

Step-by-step explanation:

6x^2-3x

substitution

x=5

6* (5*5) -3*5

6*25-3*5

150-15= 135

dsp732 years ago

5 0

Answer:

Yes, it's 135.

Step-by-step explanation:

6(5^2)-3(5)

6(25)-15

150-15= 135.

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Diedre drew a quadrilateral with 4 right Angles and opposite sides of the same length. Name all the kinds of polygons that could

Aleksandr-060686 [28]

Answer:

The answer to the question is

The kinds of polygons that could be Diedre's quadrilateral are rectangle and square

Step-by-step explanation:

We note the conditions of the polygon as thus

Number of sides = 4, Which include trapezoid, square, rectangle

Size of angles = 90 ° which eliminates trapezoid

Sizes of opposite sides = Equal opposite sides, includes square and rectangle

With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square

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2 years ago

The coordinates of triangle GBW are G (20, 10) B (-35, 20), and W (5,-10). Is GBW a right triangle? Justify your answer.

Artist 52 [7]

We know from Pythagoras' Theorem, a right angle triangle can be identified by the relationship:

$a^2+b^2=c^2$

Thus, we know if the side lengths of the triangle in question abide by this relation, the triangle is right.

First, we must find the greatest side length.

We know, using the distance formula.

$GB= \sqrt{(-35-20)^2 +(20-10)^2} =\sqrt{3125}$
$BW= \sqrt{(5+35)^2 +(-10-20)^2} =\sqrt{2500}$
$WG= \sqrt{(20-5)^2 +(10+10)^2} =\sqrt{625}$

From this, we know that:
$GB\ \textgreater \ BW\ \textgreater \ WG$
Therefore, GB would be the hypotenuse of the triangle.
Now we substitute the values for the two shorter lengths and the greater length into the pythagorean theorem:
$a^2+b^2=2500+625=3125$
$c^2=3125$
$\therefore LHS=RHS$
Therefore, this triangle is a right angled triangle

6 0

2 years ago

What is the value of X?

Paul [167]

Answer:

x = 41 ft

Step-by-step explanation:

35(35+23) = 29(29+x)

2030 = 29(29+x)

70 = 29 + x

x = 41 ft

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2 years ago

The vertices of triangle rst are r(–1,–2), s(2,–1), and t(4,2). If δjkl ∼ δrst and the length of kl is units , what is the lengt

NemiM [27]

Answer:

3.16 units

Step-by-step explanation:

It has been given that the triangles JKL and the triangle RST are congruent.

That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.

Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are $(-1,-2)$ and $(2,-1)$ .

The length of the side RS is equal to the distance between point R and S.

RS $=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$= \sqrt{(2-(-1))^2+(-1-(-(-2))^2}$

$=\sqrt{3^2+(-1+2)^2}$

$=\sqrt{9+1}=\sqrt{10}=3.16$

Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.

7 0

2 years ago

Read 2 more answers

Angle A and B are supplementary. Angle a has a measure of 80. What is the measure of angle B? The measure of angle B is

ololo11 [35]

Well when two angles are supplementary they equal 180.
So if angle A is 80 degrees then that would mean that angle B equals 100 degrees.

Hope This Helped :)

4 0

2 years ago