Answer:
The volume of the sawdust pile is 16041.7 feet.
Step-by-step explanation:
The sawdust pile formed is in the form of a cone.
The volume of a cone is:
The information provided is:
<em>r</em> = radius of the base = diameter ÷ 2 = (35 ÷ 2) feet
<em>h</em> = height = 50 feet
Compute the volume of the sawdust pile as follows:
Thus, the volume of the sawdust pile is 16041.7 feet.
Answer:
25 units
Step-by-step explanation:
This problem can be solved by using concept of Basic proportionality theorem.
This theorem states that if there is line drawn parallel to any side of the triangle, and it intersect the other two sides, then
segment divided on those two sides are in equal proportion.
Let naem this triangle
the side containing 15 and 6 be AB, with A be point on segment having length 15 units
B be point on segment having length 6 units
c be point on segment having length ? units
DE line parallel to BC
Thus, if apply Basic proportionality theorem. in this then ratio formed will be
15/6 = ?/10
5/2 = ?/10
?= 5/2* 10 = 25
The length of missing segment is 25 units.
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
Answer:
1556963
Step-by-step explanation:
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Answer: $48.93
Step-by-step explanation: 789.18 x 0.062
