Factorize the numerator and denominator. You'll see that they both have a factor of 4 that can be canceled. The introduce a factor of 3 to change the denominator to 36.

It 19/15 and or in decimal form it 1.26 and in mix number form it is 14/15
The correct question is
The sum of 5 consecutive integers is 505. What is the third number in this sequence?
Let
x-----------> first integer
x+1-----------> second integer
x+2-----------> third integer
x+3-----------> fourth integer
x+4-----------> fifth integer
we know that
x+(x+1)+(x+2)+(x+3)+(x+4)=505
then
5x+10=505----------> x=(505-10)/5---------> x=99
therefore
the third integer is (x+2)------> 99+2=101
the answer is 101
Answer:
f(7) = 2
Step-by-step explanation:
3f(7) + f(7)g(7) = 18
3f(7) + f(7)(6) = 18
f(7) (3 + 6) = 18
f(7) x (9) = 18
f(7) = 2
The given equation is (1/2)a + (2/3) b = 50
and b = 30
Substituting the given value of b is above the equation we get



Therefore, a = 60 and b = 30 is a solution of the given equation.
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