Answer:
The result of the integral is 
Step-by-step explanation:
We are given the following integral:
I am going to solve by substitution, using 
, so 
. So, we have
Which has the following result:
Going back to x, the result of the integral is
Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error M is given by:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
52% of Independents in the sample opposed the public option.
This means that 
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when 
. So
A sample size of 6755 or higher would be appropriate.
Answer:
16%
Step-by-step explanation:
add all of them together (total=18) and divide 3 by the total
You will get 0.16 and you turn it into a percentage by moving the decimal two places to the right
Answer:
You don't have a question but I'll answer what I can.
half-life = natural log (.5) / k
half-life = -.693147 / .1247
half-life = 5.561106656
It seems you did not express the k-value properly.
1) A k-value should have a negative value.
2) A k-value should also have units.
For example, the k-value of tungsten 181 is
-0.005723757 / days
Step-by-step explanation:
Answer:
Step-by-step explanation:
a) False
b) True; the graph has a v-shape and there is a portion of the graph for every possible x
c) True. And the function increases on (0, infinity)
d) true, this function is even
e) true; there are no breaks anywhere in the graph
