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Pepsi [2]
2 years ago
14

Given that f(x)=2x^3+x-3, evaluate the function f(-2). A.) 11 B.) -69 C.) -21

Mathematics
2 answers:
prohojiy [21]2 years ago
7 0
F(x)=2x³+x-3
f(-2)=2(-2)³+(-2)-3
f(-2)=2(-8)-2-3
f(-2)=-16-2-3
f(-2)=-18-3
f(-2)=-21. As a result,C is your final answer. Hope it help!
Nostrana [21]2 years ago
5 0
F(x) = 2x^3 + x - 3
f(-2) = 2(-2)^3 +(-2) -3
f(-2) = 2(-8) -2 - 3
f(-2) = - 16 - 2 - 3
f(-2) = -21
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A

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Answer:

V ≈ 37.7 ft³

Step-by-step explanation:

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4 0
2 years ago
Simply the attached question​
Finger [1]

Answer:

=x⁴−x³−14x²

Step-by-step explanation:

<h3>Let's simplify step-by-step.</h3>

x²(3x²+5x−4)−2x²(x²+3x+5)

<h3>Distribute:</h3>

=(x²)(3x²)+(x²)(5x)+(x²)(−4)+−2x⁴+−6x³+−10x²

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

<h3>Combine Like Terms:</h3>

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

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6 0
2 years ago
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Mariana [72]
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7 0
3 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7291

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have s = 5, n = 20. So

M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0
3 years ago
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