a. The standard error is equal to the standard deviation divided by the square root of the sample size:
SE = (23 ppm)/√18 ≈ 5.42 ppm
b. The t statistic is given by the difference between the true and sample means, divided by the standard error:
t = (192 ppm - 180 ppm)/SE ≈ 2.21
c. The p-value is approximately 0.0204.
d. Since p < 0.05, the difference is significantly different, so we reject the null hypothesis.
e. A type I error might have occurred, since it's possible that the null hypothesis was true, but we ended up rejecting it.
Not sure
te rate is r
for decay, it is
A=P(1-r)^t
r=rate
P=present amount
dunno what b is
but I guess
A=28000(1-0.13)^t
A=28000(0.87)^t
I would guess the decay factor would be 0.87
Answer:
(2,4)
Step-by-step explanation:
i just took the test your welcome
Plug in the values 1,4, and 9 into the equation one by one. Plug it in as the x value.
y=-1/2 times root 1 = -1/2
(x,y)=(1,-1/2)
y=-1/2 times root 4 = -1
(x,y)=(4,-1)
y=-1/2 times root 9 = -3/2
(x,y)=(9,-3/2)
