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Flura [38]
4 years ago
15

Unlike a phonograph record that has a constant angular speed, a CD scans information at a constant linear speed (130 cm/s). Does

a CD therefore rotate at a constant angular speed, or varying angular speed?
Physics
1 answer:
Oksi-84 [34.3K]4 years ago
6 0

Answer: A CD rotate at a varying angular speed

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A forward horizontal force of 12n is used to pull a crate across a horizontal floor at a constant velocity. If the crate weighs
kow [346]

Explanation:

μ = coefficient of friction.

F = Frictional force = 12N

R = Normal reaction = mg = Weight = 240N

m = mass

g = acceleration due to gravity ≈ 9.8ms—²

μ = F/R

<em>μ </em><em>=</em><em> </em><em>1</em><em>2</em><em>/</em><em>2</em><em>4</em><em>0</em>

<em>μ </em><em>=</em><em> </em>¹/20

μ = 0.05

6 0
2 years ago
If heat Q is required to increase the temperature of a metal object from 4 ∘C to 7∘C, the amount of heat necessary to increase i
alisha [4.7K]

Answer:

4Q

Explanation:

Case 1 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 7 - 4 = 3 C

Amount of heat required for the above change of temperature is given as

Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c

Case 2 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 19 - 7 = 12 C

Amount of heat required for the above change of temperature is given as

Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q

Hence the correct choice is

4Q

6 0
3 years ago
Read 2 more answers
A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled an initial speed of 2.00 m/s . The coefficient o
kobusy [5.1K]

2.04 meters distance is traveled by the sled before stopping.

Mass of the sled = m

The initial speed of the sled = 2 m/s

Coefficient of kinetic friction between sled and ice = 0.100

Let the distance the sled moves before it stops be d.

Gravity = 9.8 m/ s²

Let the initial kinetic energy sled be

= K _{i}

K_{i} =  \frac{1}{2} mv ^{2}

The work done by the frictional force is,

Work \: done \:  by \: frictional \: force =W_{f}

W _{f} = μ_{k}mgd

Work done by frictional force= Initial kinetic energy of the sled

W_{f} = K_{i}

μ_{k}mgd= \frac{1}{2} mv ^{2}

So, the distance traveled by the sled before stopping is

d= \frac{1mv ^{2} }{2 \:μ_{k}mg}

d= \frac{1v ^{2} }{2 \:μ_{k}g}

d= \frac{2^{2} }{2  \times \:0.100 \times 9.8}

d= 2.04 \: m

Therefore, the distance traveled by the sled before stopping is 2.04 meters.

To know more about work done, refer to the below link:

brainly.com/question/13662169

#SPJ4

5 0
2 years ago
When air is warm, it rises and leaves an area of low pressure which becomes filled with sinking cold air. After a hot, sunny day
expeople1 [14]
<span>Cool air from the shore will travel to the sea</span>
8 0
3 years ago
Read 2 more answers
I need some help with my science homework about energy, work, and power. It would be greatly appreciated :)
fgiga [73]

Answer:

1. B

Explanation:

Work = Force × Distance

Work = 4N × 1.5M

5 0
4 years ago
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