HELP PLEASE what is the total resistance an current in the diagram below
1 answer:
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Answer:
At the point of dropping the object, by Newton's first law due to gravitational force = m × g, accelerates
By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)
As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out
The body then moves at a constant uniform motion down according to Newton's first law
Explanation:
At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g
As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force
Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.
Answer:
Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day
Part (b) The specific discharge of the flow is 0.0363 m/day
Part (c) The average linear velocity of the flow is 0.242 m/day
Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours
Explanation:
Part (a) the flow rate per unit width of the aquifer
From Darcy's law;
where;
q is the flow rate
K is the permeability or conductivity of the aquifer = 25 m/day
b is the aquifer thickness
dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m
dl is the change in the horizontal hight = 1000 m
q = -(25*30)*(-1.45/1000)
q = 1.0875 m³/day
Part (b) the specific discharge of the flow
V = 0.0363 m/day
Part (c) the average linear velocity of the flow assuming steady unidirectional flow
Va = V/Φ
Φ is the porosity = 0.15
Va = 0.0363 / 0.15
Va = 0.242 m/day
Part (d) the time taken for a tracer to travel the distance between the observation wells
The distance between the two wells = 1000 m
average linear velocity = 0.242 m/day
Time = distance / speed
Time = (1000 m) / (0.242 m/day)
Time = 4132.23 days