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3 years ago

What is the value of the underlined digit 16,403 with the number 1 underlined

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

The value of the 1 in 16,403 is 10,000. It's in the ten thousands place. It tells you there is one set of ten thousand.

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Which equation could be used to find the length of the hypotenuse?

Komok [63]

Answer:

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Therefore,

2²+5² = c² will be matched.

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2 years ago

I have a question for 7th grade math that is do today.The math question is what is 56+(-56)=? I would guess it equals 0 but am I

qaws [65]

Answer:

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3 years ago

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Given the equation below, solve for the variable t.<br><br> p+o−wt=4b

kotegsom [21]

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mark as brainliest if it’s helpful

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3 years ago

What's an equivalent expression to 4(c+9)

sineoko [7]

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6 0

2 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

$(\left {{20} \atop {2}} \right. )$ $=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

$(\left {{3} \atop {2}} \right. )$ $=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$\frac{3}{190}\\ =0.01579\\=0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

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1 year ago