Answer:
The height of the trough is about 1.5 ft
Step-by-step explanation:
If each cubic foot of water contains about 7.5 gallons.
Then; 315 gallons is about ![\frac{315}{7.5}=42ft^3](https://tex.z-dn.net/?f=%5Cfrac%7B315%7D%7B7.5%7D%3D42ft%5E3)
Let h be the height of the trough, then
![7\times 4\times h=42](https://tex.z-dn.net/?f=7%5Ctimes%204%5Ctimes%20h%3D42)
This implies that;
![28h=42](https://tex.z-dn.net/?f=28h%3D42)
Divide both sides by 28 to get:
![h=\frac{42}{28}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B42%7D%7B28%7D)
![\therefore h=1.5](https://tex.z-dn.net/?f=%5Ctherefore%20h%3D1.5)
The height of the trough is about 1.5 ft
To answer this question, you need to determine the altitude difference and speed difference of plane B and plane A.
The initial altitude difference should be: 5000 feet- 3586 feet= 1414 feet.
The speed difference should be: 30.25 ft/s - 55.5 ft/s= - 25.25ft/s
After that, you can determine how long will pass before the plane in the same altitude.The calculation would be:
Final altitude difference= Initial altitude difference + speed difference*time
0 ft= 1414 ft + (-25.25ft/s * time)
25.25 time= 1414s
time= 56 second
To determine the altitude you just need to sample either plane A or plane B. Let's use plane B for easier initial altitude. The calculation would be:
Final altitude= initial altitude + speed*time = 5000ft + 30.25ft/s *56s= 6694ft
First you would divide $2.09 by 12 and you would get 0.17 as the answer then you would multiple 0.17 times 18 and you get the answer of $3.06