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OleMash [197]
3 years ago
14

James and Lin got married and got new jobs. Lin earns $3300more per year than James. Together they earn $82,180, How much does e

ach of them earn per year?
Mathematics
1 answer:
Len [333]3 years ago
3 0
82180 divided by 2=40,640
40,640-3300= $37,340 which is James salary
40,640+3300= $43,940 Lin’s Salary
Check/ $37,340+43,940 =$82,180
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Please help me <br> Thank you.
Svetach [21]

Answer:

(8, -1)

General Formulas and Concepts:

<u>Algebra I</u>

  • Reading a coordinate plane
  • Coordinates (x, y)
  • Solving systems of equations by graphing

Step-by-step explanation:

Where the 2 lines intersect is the solution to the systems of equations. The systems of equations intersect at (8, -1).

3 0
3 years ago
An initial population of 460 quail increases at an annual rate of 21%. Write an exponential function
Georgia [21]

Answer:

the expected population after 3 years is 863.7009

Step-by-step explanation:

The computation of the expected population after 3 years is shown below

P = P_0 × e^rt

where,

r = 21% = 0.21

t = 3 years

P_0 = 460

Now place these values to the above formula

P = 460 × exp(0.21 × 3)

= 863.7009

hence, the expected population after 3 years is 863.7009

We simply applied the above formula so that the correct value could come

And, the same is to be considered

5 0
3 years ago
Can someone help me with this question please.
kifflom [539]
The answer would most defiantly be “21”, choice c “21”
8 0
4 years ago
Read 2 more answers
The value of new cars at a local dealership is normally distributed with a mean of $34,600 and a standard deviation of $3,000. W
Vinvika [58]

Answer:

The percentage that a new car is expected to have a sticker price of between $31,600 and $40,600 is 81.86%.

Step-by-step explanation:

The random variable <em>X</em> is defined as the value of new cars at a local dealership.

The mean of the random variable <em>X</em> is, <em>μ</em> = $34,600 and the standard deviation is, <em>σ</em> = $3,000.

The random variable <em>X</em> is normally distributed.

Compute the probability that a new car is expected to have a sticker price of between $31,600 and $40,600 as follows:

P(31600

The percentage is, 0.8186 × 100 = 81.86%.

Thus, the percentage that a new car is expected to have a sticker price of between $31,600 and $40,600 is 81.86%.

7 0
3 years ago
Y’all please help me with this I don’t understand
lakkis [162]

Answer: x=12

Step-by-step explanation:

3 0
3 years ago
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