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Ad libitum [116K]
3 years ago
11

What is the measure of ∠SPQ in this rhombus?

Mathematics
2 answers:
Gemiola [76]3 years ago
5 0
Ok so all you have to do is set SPR and QPR equal like this
4x+11=5x-4
and solve to get x=15
then substitute in 15 for x in both equations
4(15)+11 and 5(15)-4
both =71 and add them up to get SPQ=142.
Serga [27]3 years ago
3 0

Answer:

Confirmation to Ziexlie's answer! Thank you!!

Step-by-step explanation:

Look at the pic :)))

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The equation of line m is 3x−5y=−4
vaieri [72.5K]
Slope of this line, -5y = -3x - 4
y = 3/5x + 4/5
So, slope of line which is perpendicular = -5/3  [reciprocal & opposite ]

In short, Your Answer would be -5/3

Hope this helps!
4 0
3 years ago
Can somebody please get me the answer to this?
Advocard [28]

Answer:

x = 15 , y = 105 ,z= 105

Step-by-step explanation:

i dont think you need explanation for all this

7 0
2 years ago
What is the zero of the following function, f(x) = –(2/7) x − 10? ​
Stels [109]

Answer:

Step-by-step explanation:

the zeros of a function f are found by solving the equation f(x) = 0. Example 1. Find the zero of the linear function f is given by. f(x) = -2 x + 4 I hope this helps.

7 0
3 years ago
3 Ramón makes nectar for a hummingbird feeder by mixing 8 cups of water with 2 cups of sugar. Tiffany makes nectar by mixing 9 c
Butoxors [25]

Answer:

Tiffany's nectar is more sugary

Step-by-step explanation:

Given

Ramon:

Water = 8\ cups

Sugar = 2\ cups

Tiffany

Water = 9\ cups

Sugar = 3\ cups

Required

The nectar with more sugar

To do this, we simply calculate the fraction of sugar in both nectar.

This is calculated as:

Fraction = \frac{Sugar}{Sugar + Water}

For Ramon:

Fraction = \frac{2}{8 + 2}

Fraction = \frac{2}{10} = 0.20

For Tiffany

Fraction = \frac{3}{3 + 9}

Fraction = \frac{3}{12} = 0.25

From the calculations above:

0.25 > 0.20

Hence: Tiffany's nectar is more sugary

5 0
3 years ago
Is the following shape a right triangle? How do you know?
vladimir1956 [14]

Answer:

C.

Step-by-step explanation:

The only information you really need in order to determine if this is a right triangle are the slopes of segments AB and BC.  If the slopes of these segments are opposite reciprocals of one another, then the lines are perpendicular, and the angle is a right angle (making the triangle a right triangle!).  Point A has coordinates (-5, 5), B(-3, 2), C(-6, 0).

The slope of segment AB:

m=\frac{2-5}{-3-(-5)}=-\frac{3}{2}

The slope of segment BC:

m=\frac{0-2}{-6-(-3)}=\frac{2}{3}

As you can see, the slopes are opposite reciprocals of one another so angle ABC is a right angle, and triangle ABC is a right triangle.  Choice C is the one you want.

5 0
3 years ago
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