1 ) Billy walks 15 miles every day to soccer practice and he had 5 practices last week.
We know that, 1 mile = 1760 yards
So, 15 miles = (15× 1760) yards = 26400 yards
Thus the total distance walked in 5 practices will be: 
2) Mark's current age is 
years
So, his age was in 10 years ago 
Given that, his current age is 3 times his age 10 years ago.
So, the equation to represent this situation will be : 
<h2>
Dimension of box is 2 m x 2 m x 1.33 m</h2>
Step-by-step explanation:
Let a be base side and h be the height.
Volume of box, V = a²h
The sides of the box will cost $3 per m² and the base will cost $4 per m². Cost for making is $48.
That is
4a² + 3 x 4 x a x h = 48
4a² + 12 a x h = 48
a² + 3 ah = 12
So volume is
At maximum volume we have derivative is zero,
Negative side is not possible, hence side of square base is 2m.
Substituting in a² + 3 ah = 12
2² + 3 x 2 x h = 12
h = 1.33 m
Dimension of box is 2 m x 2 m x 1.33 m
The volume, surface area and the ratios of the SA to volume will be as follows:
Volume=πr²h
Area=2πr²+πdh
Ratio of SA to volume=Area/volume
π=3.14
Thus using the above formula:
1.
a]
Radius: 3 inches
Height: 2 inches
Volume=πr²h
volume=π×3²×2=56.52 in³
b]
Area=2πr²+πdh
2×π×3²+π×2×3×2
=56.55+37.68
=94.23 in²
c]
Ratio=area/volume
=94.23/56.52
=1.6672
1.
Radius: 2 inches
Height: 9 inches
a]
V=πr²h
V=3.14*2^2*9
V=113.04 in³
b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*2*2*9
=25.12+113.04
=138.16 in²
c]
Ratio=area/volume
=138.16/113.04
=11/9
3.
Diameter=4 inches
Height= 9 inches
a]
V=πr²h
V=3.14×2²×9
V=113.04
b]
Area=2πr²+πdh
=2*3.14*2^2+3.14*4*9
=25.12+113.04
=138.16 in²
c]
Ratio=area/volume
=138.16/113.04
=11/9
4]
Diameter: 6 inches
Height: 4 inches
a]
Volume=πr²h
=3.14×3²×4
=113.04 in³
b]
Area=2πr²+πdh
=2×3.14×3²+3.14×6×4
=56.52+75.36
=131.88 in²
c] Ratio
131.88/113.04
=7/6
1. For the surface area to volume to be small it means that the area is smaller than the volume, for surface area to volume be larger it means that the surface area is larger than the volume. It is more economical for the surface area to volume to be small because it will mean that small amount of materials make cans with large volume. This means cost of production is cheaper.
2. To evaluate this process let's use one of the dimensions:
Radius: 3 inches
Height: 2 inches:
i. add radius and height:
3+2=5 inches
ii. Multiply radius and height:
3×2=6
iii. Dividing the result from step 1 by the result in step 2:
5/6
iv. Multiply the result from step 3 by 2:
5/6×6
=5
This result does not seem to add up to the result in our earlier ratio. Thus we conclude that Khianna was wrong. This method can't work with 3-D figures.
Answer:
b and 288
Step-by-step explanation:
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