Answer:
The table is attached!
Step-by-step explanation:
- 6 students play both musical instrument and a sport
- 3 students play neither a musical instrument nor a sport
- 14 students in total play a sport
Given: There are 24 students in the class
The number of students that does not play a sport is 24 - 14 = 10
The number of students that does not play a musical instrument but play a sport = 14 - 6 = 8
The frequency table thus is attached below:
Find the nth term of each of the sequences.<br>
(a) 16, 19, 22, 25, 28, ...<br>
(b) 1,3,9,27,81,...
juin [17]
Answer:
a) 16, 19, 22, 25, 28, 31, 34, 37, 40
b) 1, 3, 9, 27, 81, 243, 729, 2187
<h3>Explanation:</h3>
a) Add 3 on every number.
b) Multiply every number by 3.
Step-by-step explanation:
we see f(x), which is |x|.
and we see g(x), which is clearly the same basic graph, it is just shifted 3 units down in y direction.
shifts are simply done by keeping the original function definition and then add it subtract a certain constant that then adapts every original functional value.
so, a shift down by 3 units is done by adding -3.
therefore, C is the correct answer (the original f(x) - 3).
Answer:
Game 2
Step-by-step explanation:
Each hit the points would double (point(x2))
Example:
1x2=2, 2x2=4, 4x2=8, 8x2= 16, 16x2=32, and so on.
Answer:
The solution of the given initial value problems in explicit form is 
and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is
It can be written as
Use variable separable method to solve this differential equation.
Integrate both the sides.
![[\because \int x^n=\frac{x^{n+1}}{n+1}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cint%20x%5En%3D%5Cfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%5D)
... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.
The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is .
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.
