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amid [387]
3 years ago
5

2.789 in expanded form

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0
It is...........

2.789=2 ones and 7 tenths 8 hundreths 9 thousandths
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Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
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Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

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angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

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Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

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Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

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