What is the area of a circle with a diameter of 4x - 24? Specifically what steps would you take?

Mathematics

2 answers:

Natalija [7]3 years ago

5 0

Answer:

Step-by-step explanation:

The formula for the area of a circle is

A = πr². We need the radius, r, to calculate the circle.

If the diameter of the circle is 4x - 24, then the radius is half that, or

2x - 12.

Then the area of the circle in question is A = πr², or

A = π(2x -12)²

If desired, this could be expanded:

A = π(4)(x - 6)² = 4π(x^2 -12x + 36)

Marina CMI [18]3 years ago

4 0

Answer:

12.56x^2+452.16

Step-by-step explanation:

A=pie r^2

(4x-24)/2= 2x-12 which is your radius

(2x-12)^2=4x^2+144

Pie=3.14ish

3.14(4x^2+144)

12.56x^2+452.16

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1+cos2A/cos2A = tan2A/tanA prove LHS=RHS

son4ous [18]

$RTP: \frac{1 + cos(2A)}{cos(2A)} = \frac{tan(2A)}{tan(A)}$

$LHS = \frac{1 + cos(2A)}{cos(2A)}$
$= \frac{1 + \frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}{\frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}$
$= \frac{\frac{1 + tan^{2}(A) + 1 - tan^{2}(A)}{1 + tan^{2}(A)}}{\frac{1 - tan^{2}(A)}{1 + tan^{2}(A)}}$
$= \frac{2}{1 - tan^{2}(A)}$
$= \frac{2}{1 - tan^{2}(A)} \cdot \frac{tan(A)}{tan(A)}$
$= \frac{\frac{2tan(A)}{1 - tan^{2}(A)}}{tan(A)}$
$= \frac{tan(2A)}{tan(A)}$
$= RHS$ , as required.