Write a description of the data in the time line.

If Jose has 10 cookies and he ate 5 how many cookies does he have left

MAVERICK [17]

Answer: five

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

2 A square window in Miranda's

Tems11 [23]

Perimeter is , or around 63.89 in.
If you meant that the area was 225 in²:
Perimeter is 60 in

8 0

2 years ago

Which statement is true? Select all that apply.

GarryVolchara [31]

Answer:

A. The relationship is proportional.

C. The slope is negative.

✓ A. The relationship is proportional.

-> We have a one to one proportion because the relationship is linear

✗ B. The slope is –6.

-> The slope is -3/2, not -3

-> We can pick a point, and then we count down 3 and over 2 to the next point

✓ C. The slope is negative.

-> Because the line is going from top left to bottom right the line is negative

✗ D. The y-intercept is –3.

-> The slope is -3/2, not -3

-> We can pick a point, and then we count down 3 and over 2 to the next point

✗ E. The equation of the line is y = –3x.

-> Again, the slope should be -3/2, not -3

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0

2 years ago

X-5=17??????????????????

yKpoI14uk [10]

Answer:

x=21

Step-by-step explanation:

add 5 to both sides. it gives u 21

4 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago